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by Barry
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helpers.js ➔ findCode   B

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Complexity

Conditions 1
Paths 1

Size

Total Lines 33

Duplication

Lines 0
Ratio 0 %

Importance

Changes 2
Bugs 0 Features 0
Metric Value
cc 1
nc 1
nop 2
dl 0
loc 33
rs 8.8571
c 2
b 0
f 0
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export function earlierOf (a, b) {

            


            
                                                                                                            
                            
            
                                    
            
            

                
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  // inspects the .start property of a and b and returns the one

            


            
                                                                                                            
                            
            
                                    
            
            

                
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  // with the lowest start position

            


            
                                                                                                            
                            
            
                                    
            
            

                
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  if (b.start !== -1 && (a.start === -1 || b.start < a.start)) {

            


            
                                                                                                            
                            
            
                                    
            
            

                
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    return b

            


            
                                                                                                            
                            
            
                                    
            
            

                
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  } else {

            


            
                                                                                                            
                            
            
                                    
            
            

                
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    return a

            


            
                                                                                                            
                            
            
                                    
            
            

                
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  }

            


            
                                                                                                            
                            
            
                                    
            
            

                
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}

            


            
                                                                                                            
                            
            
                                    
            
            

                
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export function replaceLineEndings (txt, CRLF) {

            


            
                                                                                                            
                            
            
                                    
            
            

                
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  // replaces line endings within txt, with CRLF if CRLF is true, otherwise just LF

            


            
                                                                                                            
                            
            
                                    
            
            

                
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  if (CRLF === true) {

            


            
                                                                                                            
                            
            
                                    
            
            

                
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    // NB can't do the replacement of '\n' with '\r\n' using regex due to javascript limitations

            


            
                                                                                                            
                            
            
                                    
            
            

                
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    let p = 0 // current position in the string

            


            
                                                                                                            
                                                                
            
                                    
            
            

                
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    let x = 0 // location of '\n' in the string

            


            
                                                        
            
                                    
            
            

                
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    let t = '' // output string

            


            
                                                        
            
                                    
            
            

                
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    while (true) {

            


            
                                                        
            
                                    
            
            

                
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      x = txt.indexOf('\n', p)

            


            
                                                        
            
                                    
            
            

                
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      if (x === -1) {

            


            
                                                        
            
                                    
            
            

                
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        // we've not got any more '\n' in the string so complete and exit

            


            
                                                        
            
                                    
            
            

                
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        t = t + txt.substr(p)

            


            
                                                        
            
                                    
            
            

                
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        return t

            


            
                                                        
            
                                    
            
            

                
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      } else if (x === 0 || txt.substr(x - 1, 1) !== '\r') {

            


            
                                                        
            
                                    
            
            

                
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        t = t + txt.substring(p, x) + '\r\n'

            


            
                                                        
            
                                    
            
            

                
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        p = x + 1

            


            
                                                        
            
                                    
            
            

                
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      } else {

            


            
                                                        
            
                                    
            
            

                
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        t = t + txt.substring(p, x + 1)

            


            
                                                        
            
                                    
            
            

                
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        p = x + 1

            


            
                                                        
            
                                    
            
            

                
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      }

            


            
                                                        
            
                                    
            
            

                
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    }

            


            
                                                        
            
                                    
            
            

                
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  } else {

            


            
                                                        
            
                                    
            
            

                
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    return txt.replace(/(\r\n)/g, '\n')

            


            
                                                        
            
                                    
            
            

                
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  }

            


            
                                                        
            
                                    
            
            

                
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}

            


            
                                                        
            
                                    
            
            

                
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